MATEMATIKA

Komek eding ayyng 13'ne mugallym jogabyny sorajak diydi. Ongki gezegem chozup bilman 2-lik aldym. indi bir 5-lijek alayynda how, gayrat eding!

ay sen diyseng diysemesengem biraz ukyrak. Gornup dura jogaby. Ozem (x-y)=0 bolsa sany nola bolup bolanok

Sagat 4 boldy hawa biraz ukymam tutyar

Menem mugallyma sho jogaby berdimda INFO ol bolsa yalngysh jogaby bashga diydi.

ay dost sening mugallymyngam ozungem bolya-da. Getir shol mugallymyngy.

bu nevela chylshyrymly,harp b/n harpy goshup yorsiniz

mugalyma ayt, name direktoryn ozune beren soragy bize chozdurjek bolyan diyip😆

mamet:
mugalyma ayt, name direktoryn ozune beren soragy bize chozdurjek bolyan diyip😆

mena ynanamok shol mugallyma,hey shu yalan sozleyandirov(shutaday.
mena matematikadan ku ku dost

Ozem soragyng jogaby yok kitapda (mugallymyng soragy alan kitabynda) , mugallym aydyar gaty angsat sorag diyyar.

Ay berekella sheyle soraglaram bolsuna

Ay berekella sheyle soraglaram bolsuna

matematika gorsem,umytsyzlyk doreyar.

wikipedia.com dan2 = 11. Let a and b be equal non-zero quantities2. Multiply through by a3. Subtract 4. Factor both sides5. Divide out 6. Observing that 7. Combine like terms on the left8. Divide by the non-zero bQ.E.D.The fallacy is in line 5: the progression from line 4 to line 5 involves division by a − b, which is zero since a equals b. Since division by zero is undefined, the argument is invalid. Deriving that the only possible solution for lines 5, 6, and 7, namely that a = b = 0, this flaw is evident again in line 7, where one must divide by b (0) in order to produce the fallacy (not to mention that the only possible solution denies the original premise that a and b are nonzero). A similar invalid proof would be to say that since 2 × 0 = 1 × 0 (which is true), one can divide by zero to obtain 2 = 1. An obvious modification proves that any two real numbers are equal.Many variants of this fallacy exist. For instance, it is possible to attempt to repair the proof by supposing that a and b have a definite nonzero value to begin with, for instance, at the outset one can suppose that a and b are both equal to one:However, as already noted the step in line 5, when the equation is divided by a - b, is still division by zero. As division by zero is undefined, the argument is invalid.

1(x-y)=2(x-y)  bolar
 
songra (x-y)'lar gysgalyar

Yalnys yeri sotayi. x-y=0. Islendik bir san nol bilen bolunenok. Inlisce undefined diyilyar. Sonun ucin ol gysgalma bolanok. 

))) eptyy ...muny Turk menkdepler de bilmeyan caga yoga ))) 5 klasda gecilyan zat ))) 0/1= 0 , 1/0 = undefined ...
yene 6eyle mysalam beryadiler... 1 den 1000 ocenli hemme sanlaryn sumasy nyace? 
mes : 1+2+3 ... +1000 GAUS'yn teoriyasyny bilyan bar bolsa 30 sekunda i6lar )))

tak 4to okan okan yene bir gezek okan...

haaa yene - de bir tema gordum Turkmenistandaky okuwcylar bilen Da6aryyurtda okayanlaryn tapawudy... inede size tapawud )))))

1=2 ... bolyan zada bu, matematikada yalnyş bolyp biler durmuşda ha gabat gelyan ka wagt 1=2 yagdaylaryna 😆

1(x-y)=2(x-y) skopkañ dashyndaky sany içindäkilere aýratynlykda köpeldilmelidir.
1) 1x-1y=2x-2y bolmaly, x=y=0 bolýan bolsa
2)10-10=20-20=0 bolýar. Islendik sany nola köpeltseñ NOL BOLÝAR.
MUGALLYMYÑDAN SORA SHULA ÝALÑYSH BOLMALY DÄL. SOÑ HABAR ETGIN.

Undefined diyip gor shol mugallymyna, dushunmese mana jan etsin ozum dushundirerinda!!!