HW

sylar· · 1.143 kez okunduteswirler.com

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 79.6 m/s at ground level. The engines then fire, and the rocket accelerates upward at 3.90 m/s2 until it reaches an altitude of 1160 m. At that point its engines fail, and the rocket goes into free fall, with an acceleration of −9.80 m/s2. (You will need to consider the motion while the engine is operating and the free-fall motion separately.)

(a) For what time interval is the rocket in motion above the ground?

(b) What is its maximum altitude?

(c) What is its velocity just before it hits the ground?

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Yayımlandığı site: teswirler.com · Kaynak: Web Archive kopyası — ertir.com, 10 Mayıs 2012 · Orijinal sayfayı gör ↗

Yorumlar 27

Efendi :
Menden hemmanize plus..! Beytmanhow. Gaharynyz gelse kellanizi stena uruñ.


minusyn name zyyany bar, kop alsan name bolya? Kop goshmak alsan name bolya?

fizikden hep 3 alirdim 😆

a) t=43.972 s b) h=1944.906 m c) v=195.244 m/s

388@0:
a) t=43.972 s b) h=1944.906 m c) v=195.244 m/s

dogrymy jogaplar ozumche chozdum

388@0:
a) t=43.972 s b) h=1944.906 m c) v=195.244 m/s

molodes. Ýöne jogaplar ýalñysh ýaly görünýär

error:
388@0:
a) t=43.972 s b) h=1944.906 m c) v=195.244 m/s
molodes. Ýöne jogaplar ýalñysh ýaly görünýär

gaty dogry error %10'ny geçenok thanx👍

Milan:
Come on guy this is a basic physics question. This is nothing more than kinetics of particles.

totally agree