HW
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 79.6 m/s at ground level. The engines then fire, and the rocket accelerates upward at 3.90 m/s2 until it reaches an altitude of 1160 m. At that point its engines fail, and the rocket goes into free fall, with an acceleration of −9.80 m/s2. (You will need to consider the motion while the engine is operating and the free-fall motion separately.)
(a) For what time interval is the rocket in motion above the ground?
(b) What is its maximum altitude?
(c) What is its velocity just before it hits the ground?
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Teswirler 27
hmmm, we need to study physics for 1 year at least, to solve such a complicated question...
Come on guy this is a basic physics question. This is nothing more than kinetics of particles.
Biri online sapaklar diyip tema açyar. Bilesi gelyandir, öwrenesi gelyandir düşünemok şu tazejeleri yuwan göryanizmi namemi bira minus goyyar. Ejizi görseler göni üstünden basmak bilen bolunyar. Türkmen da...
at least we have to know a formula to solve it.. I havent even seen physics book for 5 years
Mechanics kitaby köpräk okamaly
ele kagyz, ruçka alsama dash ederdim. :-)
9-larda bar
howa gaytam plyus goyup howeslendirmeli,
Free fall: Vf=vo-/+gt,
h=Vot-/+1/2gt2,
Vf2=Vo2-/+2gh
Hasaplaberiñ:-)
g=9.8m/s
yenil soraga 3 4 sany formlua bar hemme kinetikada ulanylyan... V final dendir V initaial ...... sholar yalyjak rezko chykya
ADS name hemme kişa minus berip çykdyn?
Bagyshlañ! Gaharym gelip otyrdym weli, iñlis mowzuk üsdesine bolaýdy. Aýyplashmañ! ;-(
Gürrün ayyplaşmakda dal. Barde biri kömek sorapdyr, beyleki agzalar bolsa kömek etjek bolupdyr. Yene biri gelip kömek soranam, kömek edenenem halamadym diyip gidipdir.
Kellan yerinde dami?
Gaýrat et + goý. Düzetde olarada, mañada kömek et!
Menden hemmanize plus..! Beytmanhow. Gaharynyz gelse kellanizi stena uruñ.
Her hili adam barda Efendi bey.
😆